[om] Bug in definition of `strict_order'
Scott L. Burson
gyro at zeta-soft.com
Wed Jul 9 23:41:38 CEST 2003
I just now learned about OpenMath as I was using Google to look for some
I seem to have found a bug in the definition of `strict_order', or more
precisely, in that of `antireflexive' on which it depends. A strict order
is irreflexive, meaning `forall(x) ~R(x, x)'. The current definition of
`antireflexive', however, says
forall(x, y) R(x, y) -> R(y, x) -> x = y
But this definition does not work as part of the definition of
`strict_order', because by irreflexivity and transitivity, there are no x, y
such that `R(x, y) & R(y, x)'. It could be written instead as something
forall(x, y) (R(x, y) = R(y, x)) -> x = y
and then it would work for both reflexive and irreflexive relations.
Please CC: me in replies as I am not on the mailing list.
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